Step 1: Understanding the Given Equations
We have four equations:
- E + E + E = 15
- E + C = 8
- C + E + B = 10
- B + C × J = ? (We need to find this)
Step 2: Finding the Values of E, C, and B
Solve for E:
From the first equation: E+E+E=15E + E + E = 15E+E+E=15
This means we are adding E three times, so we rewrite it as: 3E=153E = 153E=15
Now, divide both sides by 3: E=15÷3=5E = 15 ÷ 3 = 5E=15÷3=5
Solve for C:
From the second equation: E+C=8E + C = 8E+C=8
We already found E = 5, so substitute it: 5+C=85 + C = 85+C=8
Now, subtract 5 from both sides: C=8−5=3C = 8 – 5 = 3C=8−5=3
Solve for B:
From the third equation: C+E+B=10C + E + B = 10C+E+B=10
We already know C = 3 and E = 5, so substitute them: 3+5+B=103 + 5 + B = 103+5+B=10
Simplify: 8+B=108 + B = 108+B=10
Now, subtract 8 from both sides: B=10−8=2B = 10 – 8 = 2B=10−8=2
Step 3: Solving for B + C × J
The fourth equation is: B+C×J=?B + C × J = ?B+C×J=?
We know:
- B = 2
- C = 3
But we don’t have J yet. Since no value for J is given, we can only express the answer in terms of J.
Using the BODMAS/BIDMAS rule (which tells us to do multiplication before addition): B+(C×J)B + (C × J)B+(C×J) =2+(3×J)= 2 + (3 × J)=2+(3×J) =2+3J= 2 + 3J=2+3J
Final Answer:
2+3J
If J is given a specific value, you can substitute it in, but for now, this is the final expression.